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CSIR NET Physics Coaching Delhi

CSIR NET JRF Physical Sciences Coaching Delhi

JOINT CSIR for Junior Research Fellowship 

Eligibility for Lectureship in Physics / Physical Sciences

The Council of Scientific and Industrial Research (CSIR) conducts the UGC-CSIR NET for Science subjects to determine eligibility for lectureship and for award of Junior Research Fellowship (JRF) in order to ensure minimum standards in the teaching profession and research. 

The tests are conducted twice in a year generally in the months of June and December. CSIR has a number of fellowships to the universities for the candidates who qualify the test. The JRFs are awarded to the meritorious candidates from among the candidates qualifying for eligibility for lectureship in the NET.

CSIR NET / JRF Schedule:

CSIR conducts NET JRF twice in a year, in the months of June and December. Students Willing to appear in the examination shall prepare for it at least one year before applying for examination. We at CSIR NET Physics Offer Classroom & Online Education to ensure the highest success chance in the examinations

Educational Qualification
BS-4 year program/ BE/ B.Tech/ B.Pharma/ MBBS/ Integrated BS-MS/ M.Sc. or Equivalent degree with at least 55% marks for General & OBC (50% for SC/ST candidates, Physically and Visually handicapped candidates).

Candidate enrolled for M.Sc. or having completed 10+2+3 years of the above qualifying examination are also eligible to apply under the Result Awaited (RA) category on the condition that they complete the qualifying degree with requisite percentage of marks within the validity period of two years to avail the fellowship from the effective date of award.

Such candidates will have to submit the attestation format (Given at the reverse of the application form) duly certified by the Head of the Department/Institute from where the candidate is appearing or has appeared.

B.Sc. (Hons) or equivalent degree holders or students enrolled in integrated MS-Ph.D programme with at least 55% marks for General & OBC candidates; 50% for SC/ST candidates, Physically and Visually handicapped candidates are also eligible to apply.

Candidates with bachelor degree, whether Science, engineering or any other discipline, will be eligible for fellowship only after getting registered/enrolled for Ph.D/integrated Ph.D. programme within the validity period of two years.

Age Limit

The age limit for admission to the Test is as under:
  • For JRF (NET): Maximum 28 years (upper age limit may be relaxed up to 5 years in case of candidates belonging to SC/ST/Person with Disability/Female Applicants & 3 years for OBC (non-creamy layer) (As per GOI central list)).
  • For Lectureship (NET): No upper age limit.

Scheme of Test

CSIR-UGC (NET) Exam for Award of Junior Research Fellowship and Eligibility for Lectureship shall be a Single Paper Test having Multiple Choice Questions (MCQs). The question paper shall be divided in three parts.

Part : A
This part shall carry 20 questions pertaining to General Science, Quantitative Reasoning & Analysis and Research Aptitude. The candidates shall be required to answer any 15 questions. Each question shall be of two marks. The total marks allocated to this section shall be 30 out of 200.

Part : B
This part shall contain 25 Multiple Choice Questions (MCQs) generally covering the topics given in the Part A (CORE) of syllabus. Each question shall be of 3.5 Marks. The total marks allocated to this section shall be 70 out of 200.Candidates are required to answer any 20 questions.

Part : C
This part shall contain 30 questions from Part B (Advanced) and Part A that are designed to test a candidate's knowledge of scientific concepts and/or application of the scientific concepts. The questions shall be of analytical nature where a candidate is expected to apply the scientific knowledge to arrive at the solution to the given scientific problem. A candidate shall be required to answer any 20. Each question shall be of 5 Marks. The total marks allocated to this section shall be 100 out of 200.

There will be negative marking @25% for each wrong answer.

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